JEE Main 2020 Result for January session was declared on January 23 for Paper 2 and 3, while JEE Main 2020 Result for Paper 1 was released on January 17. JEE Main Result 2020 was released as Raw Scores obtained by the candidates and converted into Normalized Scores.
Latest: Mr Ramesh Pokhriyal confirmed that JEE Main 2020 will be conducted from 18th July to 23rd July 2020. He made this announcement through the live webinar on 5th May 2020. Admit cards will be released two weeks before the examination.
Candidates would need their JEE Main 2020 Application Form, Date of Birth along with the security pin to view their JEE Main Result Scorecard. Along with the JEE Main 2020 Result, a list of candidates scoring 100 percentile and state wise toppers will be released by NTA. Scorecard will not be dispatched through mail or post to aspirants who appear for the exam.
Check Revised JEE Main 2020 Exam Pattern
Events | January Exam session | April Exam session |
---|---|---|
Exam Dates | January 6 to 11, 2020 | 18th July to 23rd July 2020 |
Release of Answer Key and OMR Sheets | 3rd week of January 2020 | To be announced |
JEE Main 2020 Result declaration for January session - Paper 1 | January 17, 2020 | To be announced |
JEE Main 2020 Result declaration for January session - Paper 2 and 3 | January 23, 2020 | To be announced |
Candidates can check their JEE Main 2020 Result online by following these steps given below:
Candidates have to visit the official JEE Main website to check their JEE Main 2020 Result online.
Enter application number, password/date of birth after clicking the JEE Main Score tab.
After the required details are submitted by the candidates, they can get access to their JEE Main Scores online
Candidates can then print/download their scorecards
The JEE Main 2020 Result is only available on the official JEE Main or NTA websites and nowhere else
The JEE Main scorecard is necessarily required for the candidates, to begin with, their JEE Main Counselling
Candidates will find the following details in their JEE Main 2020 Result Scorecard -
The JEE Main 2020 cut-offs expected by some prominent coaching centers for the year is accumulated below:
Coaching Institute | JEE Main 2020 Expected Cut off (Paper 1) |
---|---|
Toppr | Between 95 - 105 |
Basic First | 80 (+/-5%) |
Career Launcher | 75 - 80 |
FIITJEE | Around 86 |
Sri Chaitanya | Open Category - >=80 OBC - >=45 SC - >=30 ST - >=25 |
Resonance | Open Category - 70 OBC - 38 SC - 28 ST - 25 |
Motion IIT | General - 82 - 90 OBC - 55 - 60 SC - 38 - 42 ST - 32 - 38 |
Category | Cut-off |
---|---|
Common Rank List (CRL) | 81-87 |
Economically Weaker Section (EWS) | 78-83 |
Other Backward Class (OBC-NCL) | 48-54 |
Scheduled Caste (SC) | 33-35 |
Scheduled Tribe (ST) | 30-36 |
People with Disability (PwD) | 0.113 |
Number of applications received in the JEE Main 2020
Number of questions asked in the question paper
Performance of the candidates
The difficulty level of the examination
Previous years cut off trends
Relative merit list
The NTA will be releasing the scores using the normalisation procedure which is used to compare JEE Main 2020 Result using multi-session papers. This procedure is used so as to eliminate the variable difficulty of the exam, thereby eradicating any advantages/ disadvantages that some particular candidates may get over the others.
The percentile score will be based on the relative performance of all the aspirants appearing in the exam. The score will be obtained after transforming the scores into a scale ranging from 100 to 0 for each session of examinees.
As per the official website, "The Percentile Score indicates the percentage of candidates that have scored EQUAL TO OR BELOW (same or lower raw scores) that particular Percentile in that examination. Therefore the topper (highest score) of each session gets the same Percentile of 100 which is desirable. The marks obtained in between the highest and lowest scores are also converted to appropriate Percentiles."
The formula to calculate JEE Main 2020 Score is given as:
100 x number of candidates appeared in the “session” with a raw score equal to or less than the candidate/Total number of candidates appearing the particular session |
Therefore, the highest scorer always gets 100th Percentile that also means 100% candidates have scored equal to or less than raw score of 75 and 0% of candidates have scored more than 75 raw score.
A candidate with 90.1224411 Percentile Score and 71 Raw Score means that 90.1224411% candidates scored equal to or less than 71 raw score and remaining candidates scored more than 71 raw scored.
The lowest percentile in each session depends on the total number of candidates appeared in the exam in that session.
Using the above Formula percentile for each candidate with raw score can be awarded.
Distribution of candidates into different sessions randomly so approximately the same number of candidates are allotted in each session.
Each session result would be prepared in the form of raw scores and percentile score separately for each subject i.e. Mathematics percentile, Physics percentile, Chemistry percentile and Total percentile.
The percentile scores of all the four sessions shall be merged in one forming the NTA Score.
Based on the merged percentile scores from all the sessions, NTA score, the overall merit list will be prepared.
Normalization and Percentile Scores are already good measures to lessen the occurrences of a tie. National Testing Agency will award percentile scores up to 7 decimal places to further avoid ties. Since the number of applicants is in lakhs the probability of tie increases. Hence to resolve the tie in JEE Main 2020 Result, if any, the merit shall be determined in order of preference as follows:
Candidates with higher percentile in Mathematics
Candidates with higher percentile in Physics
Candidates with higher percentile in Chemistry
Candidates age is older.
The above sequence shall be adopted until the tie is broken. The Final Ranking/Merit would be prepared after resolving the ties.
Below is a list of toppers of JEE Main 2020 Jan B.E/B.Tech paper-
NTA will be releasing the scores using the normalization procedure which is used to compare JEE Main 2020 Results using multi-session papers. This procedure is used so as to eliminate the variable difficulty of the exam, thereby eradicating any advantages/ disadvantages that some particular candidates may get over the others.
Percentile Equivalence will be used by the National Testing Agency. These percentile scores are given upon the relative performances of all the candidates. This method usually gets hold of many candidates falling under the category of the same percentile which is completely fine. The percentile score is much easier to compare the position of a candidate out of lakhs of candidates taking the examination.
JEE Main Counselling and Seat Allotment process is carried on by the Joint Seat Allocation Authority (JoSAA) which has been set up the Ministry of Human Resource Development (MHRD). The process is carried on only through the online mode and only candidates who register and further get the qualifying marks for the examination are only eligible to participate in the counselling process.
Candidates are required to choose their selected preferences along with the selected colleges of their choice. More than 100 colleges and institutions all over the country participate in the process.
2 Mock Rounds and 7 Main Counselling Rounds are conducted for the candidates. The mock rounds will help the candidates to understand the seats they may be allotted, based on the preferences that the candidates have filled.
Provisional seat allotment letter by the JoSAA
Admit card for JEE Main 2020
ID Card
Passport size photographs
JEE Main 2020 Score Card
Class XII and X Marksheets
Category certificate (if required)
Migration and character certificates issued by the schools
Proof of Date of Birth
Copy of confirmation page
Note that these dates are likely to change as the JEE Main 2020 April session has been postponed due to coronavirus outbreak which will also delay the counselling and seat allotment process.
Events | Tentative Dates |
---|---|
JEE Main 2020 Result Declaration by JoSAA Declaration of JEE Advance Results Start of Registration and Choice Filling | May 14, 2020 June 14, 2020 June 15, 2020 |
Commencement of Choice Filling for AAT 2020 | 3rd week of June 2020 |
Display of Mock Seat Allocation-1 | June 22, 2020 |
Display of Mock Seat Allocation-2 | June 24, 2020 |
End of JoSAA 2020 Registration and Choice Filling | June 25, 2020 |
Seat allocation - Round 1 Seat allocation - Round 2 Seat allocation - Round 3 Seat allocation - Round 4 Seat allocation - Round 5 Seat allocation - Round 6 Seat allocation - Round 7 (last round) | June 27, 2020 July 3, 2020 July 6, 2020 July 9, 2020 July 12, 2020 July 15, 2020 July 18, 2020 |
Online Registration- candidates have to register on the official JoSAA website using their application numbers and login ids.
Choice Filling and Locking- candidates have to choose their desired course and college in this particular step and they also have an option of editing and deleting the options that they have chosen. The locking of choices can be done after each individual round of counselling ends. Candidates are required to lock in their choices before the last dates.
Allotment of Seats, JoSAA 2020- the mock allotment is done in 2 rounds. Candidates get the seats on the basis of the merit lists and the choices of course and colleges opted by the candidates. This process is also dependent on the number of seats available.
Fee payment of seat acceptance and Acceptance of Seats- the candidates get 4 options here i.e. freeze, slide, float and withdraw. These steps can be followed based on the satisfaction of the seat that the candidate has got. The candidates can pay their fee of seat acceptance through e-challan or net banking.
Through e-challan or Net Banking, the payable fee for different categories is:
S.No | Categories | Fees (Rs.) |
---|---|---|
1 | SC/ ST/ ST-PwD/ SC-PwD/ OBC-NCL-PwD/ GEN-PwD | 20000 |
2 | Others candidates | 45000 |
Fee payment for the allotted college- after the candidate has chosen the desired college, he/she can confirm his/her seat at the college and confirm their seat at the college by paying the college fee.
Ques: What does the JEE Main 2020 Result Scorecard have?
Ans: The JEE Main 2020 Result Scorecard will have name, roll number, date of birth and category of the candidate. It will also consist of the state code eligibility, subject-wise NTA Scores, nationality and category, etc. of the candidates. The conducting authority of JEE Main reflects the category wise and All India Rank of the candidates. The JEE Main 2020 Result also contains the overall and section-wise scores of the candidates.
Ques: Will I get the bonus marks in JEE Main 2020 Result for the wrong question if I leave the question un-attempted?
Ans: If there is any wrong question in the examination, marks will be awarded to everyone appearing in the examination. If two students attempt the question but get the result which is not available as any of the options, one of them might mark a wrong answer and the other leaves the question. So, Bonus marks will be awarded to all the candidates in JEE Main 2020 Result.
Ques: Will the marks be deducted in the JEE Main 2020 Result if the candidate leaves the question un-attempted?
Ans: No, there is no deduction of marks if the candidate doesn’t attempt the question. Only +4 marks will be awarded to the candidates if they mark the correct response. There is a provision of negative marking in the MCQ type questions. -1 marks will be deducted for every incorrect response. No marks will be deducted in the incorrect NTA type question.
Ques: If a candidate appears in JEE Main twice, which marks will be considered in the 2 attempts?
Ans: JEE Main is conducted twice in a year now. If a candidate gives JEE Main twice, the best of the two scores will be considered in order to calculate the All India Rank and prepare the merit list.
Ques: How many marks should a student score in order to qualify JEE Main and appear in JEE Advanced?
Ans: Every year, NTA releases certain cut off marks that are required to qualify JEE Main and appear for the JEE Advanced. Top 2,50,000 candidates in JEE Main are eligible to appear for JEE Advanced. However, getting 120 marks are enough in order to get a decent NIT. Also, one needs to score above 75% in the Class 12th Board examination in order to appear for the JEE Advanced.
Ques: How is JEE Main Cut off calculated from JEE Main 2020 Result?
Ans: JEE Main Cut off is calculated based on various factors. The cut off is decided on the basis of the level of difficulty of examination, the total number of candidates appearing in the examination, number of seats available, previous year’s cut- off and the overall performance of the candidate. The cut-off is announced separately for all the different categories, General, SC, ST, PwD, EWS etc.
Ques: What is the average score students score in JEE Main 2020 Result?
Ans: The average marks students score in JEE Main is 100- 110 for General Category, 70- 75 for OBC category students and 30- 40 for SC and ST category students.